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Review: Branches, Branch Cuts, and Riemann Sheets

The square root function and its branches are defined as follows:

(i)
The square root function $ \lambda ^{1/2}$

Let $ \lambda=\vert\lambda \vert e^{i\theta}$ . A function is defined by giving its formula and specifying its domain. The square root function $ \lambda ^{1/2}$ is defined by

$\displaystyle \lambda^{1/2}
=\vert\lambda \vert^{1/2} e^{i\theta/2}~~~~~~~~~~\textrm{(Formula)}
$

where

$\displaystyle \theta ~\textrm{is ~any~real~number~~~~~~~~~~~~~(Domain)}
$

(ii)
The first branch of $ \lambda ^{1/2}$ .

This function, denoted by $ \sqrt{\lambda}$ , is defined by

$\displaystyle \sqrt{\lambda}
=\vert\lambda \vert^{1/2} e^{i\theta/2}~~~~~~~~~~\textrm{(Formula)}
$

where

$\displaystyle 0\le \theta <2\pi ~\textrm{~~~~~~~~~~~~~(Domain)}
$

More succinctly, we have
$\displaystyle 1^{st}~ \textrm{branch~of~} \lambda^{1/2}$ $\displaystyle \equiv$ $\displaystyle \sqrt{\lambda}$  
$\displaystyle ~$ $\displaystyle =$ $\displaystyle \vert \lambda \vert^{1/2}e^{i\theta/2}\quad 0\le \theta <2\pi$  

See Figure 4.10
Figure 4.10: The first branch of the map $ \lambda ^{1/2}$ maps the complex $ \lambda $ -plane onto the upper half of the complex $ k$ -plane
\begin{figure}\centering\epsfig{file=fig_firstbranch.eps}\end{figure}
(iii)
The second branch of $ \lambda ^{1/2}$ .

This function, denoted by $ -\sqrt{\lambda}$ , is obtained by restricting the domain of $ \lambda ^{1/2}$ to $ 2\pi \le \theta <4\pi$ . In other words, $ -\sqrt{\lambda}$ is defined by

$\displaystyle -\sqrt{\lambda}
=\vert\lambda \vert^{1/2} e^{i\theta/2}~~~~~~~~~~\textrm{(Formula)}
$

where

$\displaystyle 2\pi\le \theta <4\pi ~\textrm{~~~~~~~~~~~~~(Domain)}
$

Equivalently, the second branch is defined by

$\displaystyle -\sqrt{\lambda}
=-\vert\lambda \vert^{1/2} e^{i\theta'/2}~~~~~~~~~~\textrm{(Formula)}
$

where

$\displaystyle 0\le \theta' <2\pi ~\textrm{~~~~~~~~~~~~~(Domain)}
$

See Figure 4.11
Figure 4.11: The second branch of the map $ \lambda ^{1/2}$ maps the complex $ \lambda '$ -plane onto the lower half of the complex $ k$ -plane
\begin{figure}\centering\epsfig{file=fig_secondbranch.eps}\end{figure}
(iv)
The Riemann sheets of $ \lambda ^{1/2}$ .

The two branches $ \sqrt{\lambda}$ and $ -\sqrt{\lambda}$ are the two components of the single function $ \lambda ^{1/2}$ whose domain consists of two copies of the complex $ \lambda $ -plane. The points along the real $ \lambda $ -axis are glued together (i.e. identified) in the manner depicted in Figure 4.12.

We are forced to accept these two copies if one writes the image of $ \lambda $ as

$\displaystyle [\lambda]^{1/2}=\alpha +i \beta
$

in the $ k$ -plane of Figure 4.12. Then the first Riemann sheet consists of the set of $ \lambda $ 's for which $ \beta>0$ , while the second Riemann sheet consists of those $ \lambda $ 's for which $ \beta<0$ . These sheets are joined continuously along their positive $ x$ -axes by the requirement that the function

$\displaystyle [\lambda]^{1/2} =\vert \lambda \vert^{1/2} e^{i\theta/2}%~~~~~~~~0\le\theta<4\pi
$ (459)

be continuous for all values of $ \theta $ . As a result of this requirement the two sheets are joined in the manner depicted in Figure 4.12.

It is quite true that, by itself, the complex number $ \lambda $ does not tell whether $ \lambda $ is on the first or the second Riemann sheet. This information is found neither in the real nor in the imaginary part of $ \lambda $ . Instead, it is inferred from the square root function, Eq.(4.59) Indeed, one has

$\displaystyle 0<\theta<2\pi$   $\displaystyle ~~\Longrightarrow~~\lambda \in \textrm{1st~Riemann~sheet}$  
$\displaystyle 2\pi<\theta<4\pi$   $\displaystyle ~~\Longrightarrow~~\lambda \in \textrm{2nd~Riemann~sheet}$ (460)

The set of points $ \theta =2\pi$ lies on both Riemann sheets; so does the set of points $ \theta=0$ . However, these two sets are distinct: they lie on opposite sides of the branch cut of the upper or the lower $ \lambda $ -plane.

Figure 4.12: The map $ \lambda ^{1/2}$ whose domain consists of the upper and the lower Riemann sheets and whose range is the the complex $ k$ -plane. The circle in the first Riemann sheet gets mapped into a semi-circle in the upper $ k$ -plane, and the cirle in the second Riemann sheet gets mapped into a semi-circle in the lower $ k$ -plane. A pair of points one above the other in the two Riemann sheets gets mapped into a pair of diametrically opposite points in the $ k$ -plane. The points common to the two Riemann sheets get mapped into the real axis in the k-plane.
\begin{figure}\centering\epsfig{file=fig_riemannsheets.eps}\end{figure}

An alternative way of characterizing the square root function is to collapse its domain, the two Riemann sheets, into a single $ \lambda $ -plane. Such a simplification comes, however, at a price: the square root function is now two-valued, it has two formulas, the two branches $ \sqrt{\lambda}$ and $ -\sqrt{\lambda}$ . The domain for both of them is the $ \lambda $ -plane with a branch cut along the positive real axis across which each branch is discontinuous.


next up previous contents index
Next: Square Integrability Up: Singular Boundary Value Problem: Previous: Singular Boundary Value Problem:   Contents   Index
Ulrich Gerlach 2007-04-05