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The TE Field

The result of deriving the Maxwell TE electromagnetic field components Eqs.(6.43)-(6.44) from the $ TE$ potential Eq.(6.81), arising from the corresponding $ TE$ source - all relative to the o.n. cylindrical coordinate basis - have been consolidated into Table 6.4.


Table 6.4: The $ TE$ system: All components of any $ TE$ e.m. field $ (\vec
E,\vec B)$ , as well as those of any four-vector $ TE$ potential $ (\vec A,
\phi)$ , are derived from a single master scalar function $ \Phi ^{TE}$ . Its source scalar $ S^{TE}$ determines the vectorial charge flux vector field, which is purely transverse, i.e. it is tangent to the set of nested cylinders.
$ TE$ Potential
$ \hat A_r$ $ \hat A_\theta$      $ \hat A_z$       $ \phi $
$ \frac{1}{r}\frac{\partial \Phi^{TE}}{\partial \theta}$ $ -\frac{\partial \Phi^{TE}}{\partial r}$ 0 0
$ TE$ Electric Field
$ \hat E_r$ $ \hat E_\theta$ $ \hat E_z$
$ -\frac{1}{r}\frac{\partial }{\partial \theta}\frac{\partial \Phi^{TE}}{\partial t } $ $ \frac{\partial }{\partial r}\frac{\partial \Phi^{TE}}{\partial t} $ 0
$ TE$ Magnetic Field
$ \hat B_r$ $ \hat B_\theta$ $ \hat B_z$
$ \frac{\partial }{\partial z}
\frac{\partial \Phi^{TE} }{\partial r}$ $ \frac{1}{r}\frac{\partial }{\partial \theta}
\frac{\partial \Phi^{TE}}{\partial z}$ $ -\left(
\frac{1}{r}\frac{\partial}{\partial r} r\frac{\partial}{\partial r} +
\frac{1}{r^2}\frac{\partial^2}{\partial\theta^2}
\right) \Phi^{TE} $
$ TE$ Source
$ \hat J_r$ $ \hat J_\theta$ $ \hat J_z$ $ \rho$
$ \frac{1}{r}\frac{\partial S^{TE}}{\partial \theta}$ $ -\frac{\partial S^{TE}}{\partial r}$ 0 0


The TE master scalar $ \Phi ^{TE}$ from which this result is obtained satisfies the wave equation

$\displaystyle \boxed{ \left( \frac{1}{r}\frac{\partial}{\partial r}r\frac{\part...
...artial z^2} - \frac{\partial^2}{\partial t^2} \right)\Phi^{TE}=-4\pi S^{TE} }~.$ (686)


next up previous contents index
Next: The TM Field Up: Cylindrical Coordinates Previous: Cylindrical Coordinates   Contents   Index
Ulrich Gerlach 2007-04-05