Consider the problem
of solving
This problem is solved by solving the alternate problem
The matrix
The solution
is given by
This corresponds to expressing the solution in terms of the Green's function.
Continuing with the illustrative example from linear algebra, let us assume
that
is Hermitian. Consequently, it has a complete set of eigen vectors
, and
and the orthonormality of the eigenvectors:
That
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It is clear that the resolvent
,
Eq.(4.22), viewed as a function of the complex variable
has singularities which are located at
, the eigenvalues of
.
It follows that a contour integral in the complex
plane
around these eigenvalues will recover the spectral representation
of the identity, Eq.(4.21). The complex integration leading
to this conclusion is straight forward.
Consider the integral around the contour
,
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This formula is an expression of the following
Proposition:
If the contour encloses all singularities of the resolvent
in the complex
-plane, then the contour integral yields the
complete set of orthonormalized eigenvectors of
or (in view
of the completeness of such a set of vectors)
the resolvent of
yields, via complex integration,
the spectral representation of the identity,
where
The uniqueness of the resolvent of
guarantees this result no
matter how one obtained
in the first place. Thus,
if one
somehow can determine
, then by an integration in the
complex
-plane one can readily obtain all normalized eigenvectors of
the operator
.
Furthermore, it is worth while to emphasize that the nonexistence
of
for certain values of
, far from being a
source of trouble or dispair, is, in fact, an inordinate physical and
mathematical boon. As we shall see, from the physical point of view, the
nonexistence furnishes us with the resonances of the system, while from the
mathematical viewpoint it furnishes us with the orthonormalized eigenvectors
or eigenfunctions of the system.